Algebraic Thinking

8.1 Variables

Thinking with Variables

Algebra begins when we stop thinking only about specific numbers and start describing general patterns.

Definition: Constant

A constant is a fixed value.

Definition: Variable

A variable is a symbol that can represent one or more values.

Example: Constants vs variables

Identify constants and variables in each formula.

  1. $A=lw$
  2. $P=2l+2w$
  3. $C=2\pi r$
  4. $F=\frac95C+32$
  5. $A=Pe^{rt}$
Show Solution
  1. Variable symbols: $A,l,w$. Constants: implied 1.
  2. Variables: $P,l,w$. Constants: 2.
  3. Variables: $C,r$. Constants: 2 and $\pi$.
  4. Variables: $F,C$. Constants: $\frac95$ and 32.
  5. Variables: $A,P,r,t$. Constants: $e$.

The same symbol can be variable in one context and fixed in another; context decides role.

Example: Translate words to algebra

A car rental costs a flat $50 dollars plus 0.20 dollars per mile m. Write the cost expression.

Show Solution

Flat fee plus per-mile fee gives

$$C(m)=50+0.20m.$$

That expression can now be used for any mileage input.

MyOpenMath: MOM: Variables and translation

Arithmetic Sequences as Functions

An arithmetic sequence has constant difference d, so terms grow linearly.

Fact: Arithmetic n-th Term Formula

If first term is $a_1$ and common difference is $d$, then

$$a_n=a_1+d(n-1).$$

Example: Build sequence from two terms

An arithmetic sequence has $a_2=11$ and $a_5=23$. Find d, formula, and first terms.

Show Solution

Use term formula twice:

$$a_2=a_1+d=11$$ $$a_5=a_1+4d=23.$$

Subtract equations: $3d=12$, so $d=4$. Then $a_1=11-4=7$.

So

$$a_n=7+4(n-1)=4n+3.$$

First terms are 7, 11, 15, 19, 23, ...

Example: Another arithmetic reconstruction

Given $a_{10}=100$ and $a_{15}=145$, find formula and $a_{500}$.

Show Solution

Set up:

$$a_1+9d=100, \quad a_1+14d=145.$$

Subtract: $5d=45\Rightarrow d=9$. Then $a_1=100-81=19$.

Formula:

$$a_n=19+9(n-1)=9n+10.$$

Then

$$a_{500}=9(500)+10=4510.$$

MyOpenMath: MOM: Arithmetic sequences

Geometric Sequences as Functions

A geometric sequence has constant ratio r, so terms grow exponentially.

Fact: Geometric n-th Term Formula

If first term is $a_1$ and ratio is $r$, then

$$a_n=a_1r^{n-1}.$$

Example: Geometric sequence from two terms

Given $a_2=3$ and $a_5=81$, find formula and $a_{10}$.

Show Solution

From formula:

$$a_2=a_1r=3, \quad a_5=a_1r^4=81.$$

Divide equations: $r^3=\frac{81}{3}=27$, so $r=3$. Then $a_1=\frac{3}{3}=1$.

So

$$a_n=3^{n-1}.$$

Then

$$a_{10}=3^9=19683.$$

Example: Growth model

A bacteria culture doubles every 3 hours and starts at 500. Write formula and find amount after 24 hours.

Show Solution

In 24 hours there are $\frac{24}{3}=8$ doubling periods.

$$B(t)=500\cdot 2^{t/3}.$$

So

$$B(24)=500\cdot 2^8=500\cdot 256=128000.$$

MyOpenMath: MOM: Geometric sequences and growth